30=16x^2+112x

Solution for 30=16x^2+112x equation:

30=16x^2+112x

We move all terms to the left:

30-(16x^2+112x)=0

We get rid of parentheses

-16x^2-112x+30=0

a = -16; b = -112; c = +30;
Δ = b2-4ac
Δ = -1122-4·(-16)·30
Δ = 14464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14464}=\sqrt{64*226}=\sqrt{64}*\sqrt{226}=8\sqrt{226}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-112)-8\sqrt{226}}{2*-16}=\frac{112-8\sqrt{226}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-112)+8\sqrt{226}}{2*-16}=\frac{112+8\sqrt{226}}{-32}
$